// template8.cpp			By: Aiman Hanna -  ©1993-2006 Aiman Hanna

// This program fixes one of the problems that template7.cpp has. 
// Notice the addition of the overloaded '<' operator for the Car class.

//	Key Points: 	1) typename 


#include <iostream.h>
#include "template7.h"


template <typename Type>
Type  min( Type a, Type b )
{
 return a < b ? a : b;		// same as:  if ( a < b ) return a; else return b;
}

// Definition of the Car class
 
Car::Car(double pr) 
{
	price = pr;
}


void Car::setPrice(double pr) 
{
	price = pr;
}


// Since this function should NOT modify the class attributes, 
// it should be declared as a constant function 

double Car::getPrice() const
{
	return price;
}



bool operator<( const Car& c1, const Car& c2) 
{
	// returns true if the price of c1 is smaller than the price of c2;
	// returns false otherwise

	if (c1.getPrice() < c2.getPrice())
		return true;
	else
		return false;
}



int main( )
{
 int i1 = 10, i2 = 5;
 double d1 = 13.2, d2 = 21.9;
 char ch1 = 'f', ch2 = 'k';

 cout << " The minimum value of the two integers i1 and i2 is: " << min( i1, i2 ) 
 							             << endl << endl;
 cout << " The minimum value of the two doubles d1 and d2 is: " << min( d1, d2 ) 
 							             << endl << endl;
 cout << " The minimum value of the two characters ch1 and ch2 is: " 
							<< min( ch1, ch2) << endl << endl;

 // The following calls would be illegal, however


// cout << " The minimum value of the two values i1 and d1 is: " << min( i1, d1 ) 
// 							             << endl << endl;

// The above line would result in: 
/* error C2782: template parameter 'Type' is ambiguous, could be 'double'  or    'int'
*/



Car c1(3000), c2(7000);
cout << " The cheapest price of the two cars, c1 and c2, is: " << min( c1, c2 ).getPrice() << endl << endl; 

// Hint: You should notice the syntax of the aboive line very carefully 


return 0;
}


// The output of the program 
/*
 The minimum value of the two integers i1 and i2 is: 5

 The minimum value of the two doubles d1 and d2 is: 13.2

 The minimum value of the two characters ch1 and ch2 is: f

 The cheapest price of the two cars, c1 and c2, is: 3000

*/